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Expression for capillary rise and capillary fall - Jurin's law

 

Expression for capillary rise and capillary fall - Jurin's law

Expression for height in Capillary rise
capillary rise

Consider a narrow glass tube of diameter of d dipped in a liquid (say water). Water in the tube will rise above the adjacent liquid level. It is called capillary rise.

Let σ = Surface tension of liquid.
ϴ = Angle of contact between the glass tube and the liquid surface.
h = Height of liquid column in glass tube.

Under equilibrium, two forces are acting on the water inside. The first one is weight of water column and second is the upward force acting on water due to surface tension. The weight of liquid of height h should be balanced by the force at liquid surface. This force at surface of liquid is due to surface tension.

The weight of liquid of height h in the tube = Volume x ρ x g
= (π/4)d2 x h x ρ x g

Here ρ = density of liquid
g = acceleration due to gravity.

The vertical component of surface tensile force = surface tension x circumference x cosϴ
= σ x πd x cosϴ

At equilibrium, the weight of liquid balanced by the vertical component of tensile force.
π/4 d^2 h ρ g= σ πd cosϴ h=(4 σ cosϴ )/ρgd cappillary rise equation

For water and glass tube, the angle ϴ is almost zero. ie cosϴ ≈ 1
Then the equation for capillary rise of water in the glass tube is h = 4 σ /(ρgd)

Expression for Capillary fall

capillary fall

Consider a narrow glass tube dipped in mercury, the level of mercury in tube will be lower than the surface level of mercury outside the tube. It is called capillary depression.
Consider the mercury glass tube arrangement as shown in figure. Two forces are acting on the mercury inside the tube. First one is hydrostatic force that acting upward, and second one is downward force due to surface tension. In equilibrium condition these forces must be equal.

Let h = height of capillary depression.
The hydrostatic force on liquid = Intensity of pressure at depth h x Area
= ρ x g x h x (π/4)d2

Surface tension acting downward = Surface tension x circumference x cosϴ
= σ x πd x cosϴ
Equating two forces, we get
π/4 d^2 h ρ g= σ πd cosϴ h=(4 σ cosϴ )/ρgd capillary fall equation of height

The value of contact angle for mercury in glass tube = 128°

Remember:
👉Capillary is the result of both adhesion and cohesion.
👉Curved free surface of liquid in tube is known as meniscus.
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